TIM 001 #100 – On Delay Timer for 10sec.When both the conveyers receive 5 boxes each, then the first 2 conveyers will stop and the third conveyer will be ON for 10s.
Then both the conveyers will receive the box at every 5s. In the last comparator, if the counter value is equal to 12, the timer will start to run for 5sec and after 5sec it will turn OFF all the outputs.ħ. Consider 3 conveyers, if I switch ON the switch SW1 then the first 2 conveyers will turn ON.
To turn OFF the conveyor, we are using I0.03, I0.04 and I0.05 stop buttons in series to the start buttons and output.If any one of the start button is turned ON, the conveyer will be ON. To turn ON the Conveyor, we are using I0.00, I0.01 and I0.02 start buttons in parallel to the output Q100.00.Write a Logic to control a conveyor which has to ON when any one of the 3 start buttons is pressed, and it should stop when any one of the 3 stop buttons is pressed. To turn OFF the output Q100.00 we have to use RST coil, hence I0.01 Stop Button connected to the RST coil Output with address Q100.00.Ģ.Start button I0.00 is a Push button and it gives a pulse signal to the right side rung hence by using the SET coil we can hold the output Q100.00 in the high state, and it will be in ON state until it reset.When we are using the push button either we need to use latch to hold the output or else we can use SET and RST coil function. I0.00, I0.01 are the inputs considered as Start and Stop Button. b) Write the same ladder logic without latches.